{"id":2062,"date":"2024-08-11T07:18:15","date_gmt":"2024-08-10T23:18:15","guid":{"rendered":"http:\/\/www.jiaohuweike.online\/?p=2062"},"modified":"2024-08-11T07:18:15","modified_gmt":"2024-08-10T23:18:15","slug":"hsyldwt-5-4-2","status":"publish","type":"post","link":"http:\/\/jhwk.online\/?p=2062","title":{"rendered":"\u5e38\u7528\u903b\u8f91\u7528\u8bed"},"content":{"rendered":"\n
<\/div>\n\n\n\n
1.\u5df2\u77e5  P=\\left\\{x \\mid-x^{2}+2 x+3<0\\right\\}, Q=\\left\\{x \\mid x^{2}+(a+1) x+a>0\\right\\} , \u4e14  x \\in P  \u662f  x \\in Q  \\\\\u7684\u5145\u8981\u6761\u4ef6, \u6c42\u5b9e\u6570  a \u7684\u53d6\u503c\u96c6\u5408.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<\/pre><\/div>\n\n\n\n
\u7b54\u6848<\/summary>\n
<\/p>\n\n\n\n
\u7b54\u6848\uff1aa=-3.\u63d0\u793a\uff1a\u7531\u5145\u8981\u6761\u4ef6\u5f97P\u4e0eQ\u5bf9\u5e94\u7684\u4e0d\u7b49\u5f0f\u76f8\u540c.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<\/pre><\/div>\n\n\n\n
\n<\/details>\n\n\n\n
2.\u8bbe  f(x)=x^{2}-a x+1 \\quad(x \\in \\mathbf{R}) , \u5219\u5173\u4e8e  x  \u7684\u4e0d\u7b49\u5f0f  f(x)<0  \u6709\u89e3\u7684\u4e00\u4e2a\u5fc5\u8981\u4e0d\u5145\u5206~~~\\\\\u6761\u4ef6\u662f (~~~~~~~ ).~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\\\\\nA.  -2< a <0 ~~~~~\nB.  a < -2  \u6216  a>2 ~~~~\nC.  |a|>3 ~~~~~\nD.  |a| \\geqslant 2 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<\/pre><\/div>\n\n\n\n
\u7b54\u6848<\/summary>\n
<\/p>\n\n\n\n
\u7b54\u6848\uff1aD.\u63d0\u793a\uff1af(x)<0\u6709\u89e3\u5f97a^2>4,\u4e3a |a| \\geqslant 2\u7684\u771f\u5b50\u96c6.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<\/pre><\/div>\n\n\n\n
\n<\/details>\n\n\n\n
3.\u5df2\u77e5  p: x^{2}-8 x+15<0, q:(x-2 m)(x-5 m)<0 , \u5176\u4e2d  m>0 . \u82e5  q  \u662f  p  \u7684\u5fc5\u8981\u4e0d\u5145~~~\\\\\u5206\u6761\u4ef6, \u6c42\u5b9e\u6570m\u7684\u53d6\u503c\u8303\u56f4.  ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \\\\\n\n\n<\/pre><\/div>\n\n\n\n
\u7b54\u6848<\/summary>\n
<\/p>\n\n\n\n
\u7b54\u6848\uff1a[1,\\frac{3}{2}]\u63d0\u793a\uff1ap:A=[3,5],q:B=[2m,5m],A\u662fB\u7684\u771f\u5b50\u96c6(\u7b49\u53f7\u4e0d\u80fd\u540c\u65f6\u53d6\u5230)<\/pre><\/div>\n\n\n\n
\n<\/details>\n\n\n\n
4.\u5df2\u77e5\u547d\u9898 \"  \\exists x \\in \\mathbf{R}, a x^{2}-2 a x+3<0  \" \u662f\u5047\u547d\u9898, \u6c42\u5b9e\u6570  a  \u7684\u53d6\u503c\u8303\u56f4.~~~~~~~~~~~~~~~~~~~~~~~~~~<\/pre><\/div>\n\n\n\n
\u7b54\u6848<\/summary>\n
<\/p>\n\n\n\n
\u7b54\u6848:[0,3];\u63d0\u793a\uff1a\\forall x \\in \\mathbf{R}, a x^{2}-2 a x+3\\ge0 \u662f\u771f\u547d\u9898.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<\/pre><\/div>\n\n\n\n
\n<\/details>\n\n\n\n
5. \u8bbe\u547d\u9898  p  : \u5173\u4e8e  x  \u7684\u65b9\u7a0b  x^{2}+(a-4) x+4=0  \u5728  x \\in(0,+\\infty)  \u4e0a\u6709\u89e3, \u547d\u9898  q  : \u51fd\u6570  ~~~~~~~~\\\\f(x)=\\log _{2 a^{2}-a} x  \u5728\u5b9a\u4e49\u57df\u4e0a\u5355\u8c03\u9012\u51cf, \u82e5\u547d\u9898  p  \u548c\u547d\u9898  q  \u81f3\u5c11\u6709\u4e00\u4e2a\u4e3a\u5047\u547d\u9898, \u6c42\u5b9e\u6570  a ~ \\\\\u7684\u53d6\u503c\u8303\u56f4 .  \\qquad ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<\/pre><\/div>\n\n\n\n
\u7b54\u6848<\/summary>\n
<\/p>\n\n\n\n
\u7b54\u6848\uff1a(-\\infty ,-\\frac{1}{2} ]\\cup [0,+\\infty )\u63d0\u793a\uff1a\u547d\u9898p\u4e2d\uff0c\u5206\u79bb-(a-4)=x+\\frac{4}{x}\u5728(0,+\\infty)\u6709\u89e3\uff0c\\\\a\\le0\u3002\u547d\u9898q\u4e2d\uff0ca\\in (-\\frac{1}{2},0)\\cup(\\frac{1}{2},1),\u82e5p,q\u90fd\u4e3a\u771f\uff0c\u5219a\\in (-\\frac{1}{2},0)\uff0c\u5176\u8865\u96c6\u4e3a~~~~~~~~~~~\\\\(-\\infty ,-\\frac{1}{2} ]\\cup [0,+\\infty ).~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<\/pre><\/div>\n\n\n\n
\n<\/details>\n\n\n\n
\n